<PRE><B>Question 29177</B>
IN A RHOMBUS IF SIDE IS X WE HAVE 
(D1/2)^2+(D2/2)^2=X^2...WHERE D1 AND D2 ARE DIAGONALS
IF D1=X = 6=AB=BC=CD=DA.....GIVEN.....THEN
(X/2)^2+(D2/2)^2=X^2...
(D2/2)^2=3X^2/4
D2/2=X*SQRT3/2
D2=X*SQRT3
SO EACH DIAGONAL IS X AND X*SQRT(3) 
NOW X=6 SO 
D1=6=AC AND D2 =6SQRT(3)=10.4 =BD

FIGURE IS GIVEN BELOW
{{{drawing( 800, 800,-20,40,-20,40,red( line( 0, 0, 10,-11.2 ) ),locate( 0, 0, A ),red( line( 10, -11.2, 20,0 ) ),locate( 10,-11.2, B ),red( line( 20,0, 10,11.2 ) ),locate( 20, 0, C ),red( line( 10, 11.2, 0,0 ) ),locate( 10, 11.2, D ),green( line( 10, 11.2, 10,-11.2 ) ),green(line( 0, 0, 20,0) ) ))}}} 
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