Question 212510
 -7k<63 or 8a-15>73
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-7k < 63
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multiply both sides by -1 to get:
7k > -63 (inequality reverses when you multiply both sides by -1).
divide both sides by 7 to get:
k > -9
to graph this equation, substitute y for k.
you get:
y > -9
you graph this equation by graphing y = -9 and then looking at the graph and seeing that any points above the line are what you are interested in.
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the graph looks like this:
graph {{{graph(200,200,-5,10,-15,3,-9)}}}
the area above the graph is what you are interested in.
the horizontal line is the graph of the equation of y = -9.
the area above the line is when y > -9.
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example:
when x = 5, y = -9.  y > -9 would be all points above the line which would be all points where y > -9.
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8a-15>73
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add 15 to both sides of this equation to get:
8a > 73 + 15 which equals:
8a > 88
divide both sides of this equation by 8 to get:
a > 11
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replace a with y to be able to graph this equation.
you get:
y > 11
to graph this, you graph the equation of y = 11.
your graph is a horizontal line at y = 11
the graph looks like this:
graph {{{graph(200,200,-5,10,-3,15,11)}}}
since your equation is y > 11, then all points above this line are what you are interested in.
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example:
let x = 5.  point on the line would be y = 11.  all points above the line would be all points when y > 11.
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