Question 212517
Need help with finding the equation of the line which contains the point (0,1) and has the slope 1 ?


Step 1.  The slope m is given as


{{{m=(y2-y1)/(x2-x1)}}}


Step 2.  Let (x1,y1)=(0,1) or x1=0 and y1=1 .  Let other point be ((x2,y2)=(x,y) or x2=x and y2=y.


Step 3.  Now we're given {{{m=1}}}.  Substituting above values and variables in the slope equation m yields the following steps:


{{{m=(y2-y1)/(x2-x1)}}}


{{{1=(y-1)/(x-0)}}}


Step 4.  Multiply x to both sides to get rid of denominator on right side of equation.


{{{x=y-1}}} 


Step 5.  Now add 1 to both side of equation.


{{{x+1=y}}}


Note:  the above equation can be rewritten as 

{{{x-y=-1}}}

And the graph is shown below which is consistent with the above steps.


*[invoke describe_linear_equation 1, -1, -1 ]



I hope the above steps were helpful.  Good luck in your studies!


Respectfully,
Dr J


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