Question 212522
need help to find the equation of the line which contains the point (-1,3) and has slope negative one fifth.
:
Use the point/slope formula: y - y1 = m(x - x1)
In this problem m = {{{-1/5}}}; x1 = -1; y1 = 3
:
y - 3 = {{{-1/5}}}(x - (-1))
y - 3 = {{{-1/5}}}(x + 1)
y - 3 = {{{-1/5}}}x - {{{1/5}}}
y = {{{-1/5}}}x - {{{1/5}}} + 3
y = {{{-1/5}}}x - {{{1/5}}} + {{{15/5}}}
y = {{{-1/5}}}x + {{{14/5}}} is the equation:
:
Check this, substitute -1 for x in the above equation and find y