<PRE><B>Question 212427</B>
x-5 over x+4 = x-1 over x+3 Solve for x
Cross multiply
(x-5)*(x+3) = (x+4)*(x-1)
{{{x^2 - 2x - 15 = x^2 + 3x - 4}}}
-2x-15 = 3x-4
5x = -11
x = -11/5
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7 over x-2 + 2 over x+2 = -4x over x^2-4 solve for x 
{{{7/(x-2) + 2/(x+2) = -4x/(x^2-4)}}}
(x^2-4) = ((x-2)*(x+2) and is the common denominator
Multiply thru by (x^2-4)
7(x+2) + 2(x-2) = -4x
7x+14 + 2x-4 = -4x
9x + 10 = -4x
13x = -10
x = -10/13
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