Question 212423
I need helpe with this problem.
The sum of three consecutive odd integers is 89 more than twice the largest integer. Find the integers
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1st: 2x-1
2nd: 2x+1
3rd: 2x+3
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Equation:
2x-1+2x+1+2x-3 = 2(2x+3) + 89
6x -3 = 4x+95
2x = 98
x = 49
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1st: 2x-1 = 97
2nd: 2x+1 = 99
3rd: 2x+3 = 101
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Cheers,
Stan H.