Question 212300
Find the inverse of 


{{{y=7x^2-3}}} or {{{x=f(y)}}}


Step 1.  Add 3 to both sides of equations


{{{y+3=7x^2-3+3}}}

{{{y+3=7x^2}}}


Step 2.  Divide 7 to both sides of equations


{{{(y+3)/7=x^2}}}


Step 3.  Take square root of both sides


{{{sqrt((y+3)/7)=x}}}


Step 4.  The inverse is


{{{x=sqrt((y+3)/7)}}}