Question 29201
5x + 2y < 10
2y < -5x + 10
y < -(5/2)x + 10/2
y < -(5/2)x + 5


OK, so plot the line y = -(5/2)x + 5. This line is where y EQUALS the right hand side. Then where is the region on the graph where y is LESS than the righthand side?


If you cannot "see" the answer, look at my Lesson of Graphing Inequalities... that will help you


jon.