Question 212205
Johnny leaves Memphis to visit Anne, who lives in Hornsby, TN, 80 miles away.
 He travels at an average speed of 50 mph. One-half hour later, 
Anne leaves to visit Johnny, traveling at an average speed of 60 mph.
 How long after Anne leaves will it be before they meet?
:
Let t = Anne's travel time
then
(t+.5) = John's travel time (half hour longer the Anne)
:
When they meet, they will have traveled a total of 80 mi
:
Write a distance equation: Dist = speed * time
:
J's dist + A's dist = 80 mi
50(t+.5) + 60t = 80
50t + 25 + 60t = 80
50t + 60t = 80 - 25
110t = 55
t = {{{55/110}}}
t = {{{1/2}}} hr is A's travel time
;
:
Check solution by finding the total dist:
60*.5 = 30
50*(.5+.5) = 50 mi
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total dist 80 mi