Question 212187
Let x, x+2 & x+4 be the three consecutive even integers.
4(x+x+4)=6(x+2)-20
4(2x+4)=6x+12-20
8x+16-6x=-8
2x=-8-16
2x=-24
x=-24/2
x=-12 ans.
-12+2=-10
-12+4=-8
Proof:
4(-12-8)=6*-10-20
4*-20=-60-20
-80=-80