Question 212102
Find the x intercepts for the parabola y = x2 – 6x + 5.

Step 1.  For this problem y=0 since we want x-intercepts.  


Step 2.  Use quadratic formula:  

{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}

where a=1,  b=-6 and c= 5

Step 3.  The following steps shows how to solve the above equation in Step 2 where you will find x=1 and x=5.  Note the parabola intercepts x-axis when y=6 at these points.

*[invoke quadratic "x", 1, -6, 5 ]




Problem:  Find the vertex of the parabola y = - 2x2 + 8x + 4 


{{{ -2x^2+8x+4}}}


Step 1.  Graph is shown below and the vertex is at (2,12)

*[invoke quadratic "x", -2, 8, 4 ]


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