<PRE><B>Question 212028</B>
L=3w
2(L+w)+128=Lw
2(3w+w)+128=3w*w substitute 3w for L
8w+128=3w^2
3w^2-8w-128=0 subtract the left side of the equation from the right.
3*-128=-384 Multiply the 1st and the last coefficients.
What 2 factors of -384 give a sum of -8? Answer: -24 and 16
3w^2-24w+16w-128=0
3w(w-8)+16(w-8)=0
(3w+16)(w-8)=0 Factoring by grouping.
w=8
L=24
.
Ed</PRE>