Question 211918
This is from a chapter on solving a quadratic equation by completing a square. Please help me solve.

{{{(4)/(m^2-7)=1}}}

Step 1.  For this case completing the square was not needed.  Let's get rid of the denominator by multiplying the denominator to both sides of the equation.


The equation {{{(4)/(m^2-7)=1}}}  OR {{{(4)(m^2-7)/(m^2-7)=1*(m^2-7)}}} which will now be

  
{{{(4)=(m^2-7)}}}


Step 2.  Now let's subtract -4 from both sides of the equation.


{{{(4-4)=0=(m^2-7-4)}}}


{{{0=(m^2-11)}}}  (note: the answer is just the {{{m=sqrt(11)}}}) plus or minus sqrt(11)




Step 3.  So this is now a quadratic equation where


a=1, b=0, and c=-11 where we will use the quadratic formula


{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}

Step 4.  See the steps below to solve this.


*[invoke quadratic "x", 1, 0, -11 ]


Note:  Step-By-Step Videos in Pre-Algebra can be found at http://www.FreedomUniversity.Tv/courses/IntroAlgebra.