Question 211833
Let x, x+2 be  consecutive integers
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(x)(x+2) = 4(x+x+2) -1 = 4(2x+2)-1 
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x^2 +2x = 8x +8 -1
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x^2 -6x -7 =0
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(x-7)(x+1) = 0
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x+7,,,,-1 
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consecutive integers,,7,9,,,,,-1,1
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check,,,(7,9),,,7*9 = 4(7+9) -1 = 63,,,,ok
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(-1,1),,,,,-1*1 = 4(-1+1) -1 = -1,,,,ok
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