<PRE><B>Question 211829</B>
f Mark invests $46,000 at a rate of 6%, how much more would he have to invest at
 2% to get an average 3% return? 
:
Treat just like a mixture problem:
:
Let x = amt of $ to be added
:
.06(46000) + .02x = .03(x + 46000)
:
2760 + .03x = .03x + 1380
:
2760 - 1380 = .03x - .02x
:
1380 = .01x
x = {{{1380/.01)}}}
x = $138,000 has to be invested at 2%
:
:
Check solution in original equation:
.06(46000) + .02(138000) = .03(138000 + 46000)
2760 + 2760 = .03(184000)
5520 = 5520
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