Question 211813
A point on the circumference of a circle of radius = 2ft. rotating at 25 rpm would have a linear velocity of:
{{{25*2(pi)(r) = 50*(pi)*(r)}}} Substitute {{{r = 2}}} and {{{pi = 3.142}}}, then the linear velocity would be:
{{{v[l] = 25*2(3.142)*2}}}
{{{V[l] = 314.2}}}ft.per sec.