Question 211730
First, I must point out that your two equations are not equal.  Unless I am misunderstanding the original equation, you have given 2 different problems.

For the first equation, I understand it to read like this:
{{{2/x-1=(-6)5/x-2}}}

Start by multiplying the entire equation by x to eliminate the fraction.
{{{2-x=-30-2x}}}

To solve for x, move all the x terms to the left side of the equation and all the non x terms to the right side.

Add 2x to each side to move the -2x to the left.  Remember that what you do to one side of the equation, you have to do to the other.
{{{2-x+2x=-30-2x+2x}}}
Combine like terms to get:
{{{2+x=-30}}}
Now move all non x terms to the right side by subtracting 2 from both sides.
{{{-2+2+x=-30-2}}}   
Combine like terms again and the result is:
{{{x=-32}}}
 

For your second equation, you must use the quadratic equation to solve this problem.
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}

You've already got the equation in to {{{ax^2+bx+c}}} form, so just plug in the numbers.
*[invoke quadratic "x", 6, -21, 13 ]


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