Question 211681
{{{f(x)=8^(4x+9)}}}
{{{f(x)=8^(4x) * 8^9}}}
{{{f(x)=(8^4)^x * 8^9}}}
{{{f(x)=(8^4)^x * 8^9}}}
{{{8^-9 * f(x)=(8^4)^x}}}
log_{{{8^4}}} {{{8^-9 * f(x)}}}=x
log_{{{8^4}}}{{{8^-9}}} + log_{{{8^4}}} f(x)=x
(-9/4) + log_{{{8^4}}}f(x)=x
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So the inverse function is,
{{{f^-1(x)=(-9/4) + log_4096 (x)}}}