Question 211712
Given: two points (3,7) and (-5,-8)
Using these points, we can find the slope of the line passing through them.
{{{m=(7-(-8))/(3-(-5))=15/8}}}
Using the point slope form of the line y-k=m(x-h) where (h,k) is on the line, the equation of the line is
y-3=15/8(x-7)
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If (-33,-2/3) is on the line, it must satisfy the equation.
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(-2/3)-3=15/8(-33-7)
(-2/3)-3=15/8(-40)
(-2/3)-3=15(-5)
(-2/3)-(9/3)=-45
-11/3=-45
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This is a false statement, so the point (-33,-2/3) is not on the line.