Question 211509
{{{3*sqrt(48)-4*sqrt(27)}}}
={{{3*sqrt(3*16)-4*sqrt(3*9)}}}
={{{3*sqrt(3*4^2)-4*sqrt(3*3^2)}}}
={{{3*4*sqrt(3)-4*3*sqrt(3)}}}   Note that {{{sqrt(a*b^2)=b*sqrt(a)}}}
={{{12sqrt(3)-12sqrt(3)}}}
={{{0}}}