Question 211455
Reducing to lowest term
{{{(T^2 + 6T + 8)/(2T^2 - 8)}}}
Factor
{{{((t+4)(t+2))/2(t^2 - 4)}}} 
Note that t^2 - 4, can be factored as the difference of squares:
{{{((t+4)(t+2))/(2(t-2)(t+2))}}}
cancel (t+2)'s
{{{((t+4))/2(t-2)}}} is in lowest terms