Question 211357
u sub zero =16
u sub n=(1-0.005)u sub n-1+16
where n > or = to 1
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{{{x(0)= 16}}}
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{{{x(n) = (1-.005)*x(n-1) + 16}}}
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when n = 1, this becomes:
{{{x(1) = (1-.005)*x(0) + 16}}}
since {{{x(0) = 16}}} this becomes:
{{{x(1) = (1-.005)*16 + 16}}}
this becomes:
{{{x(1) = .995*16 + 16}}}
which becomes:
{{{x(1) = 15.92 + 16}}} which becomes:
{{{x(1) = 31.92}}}
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this assumes i interpreted your equation correctly.
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