Question 211463
4x^2 +19xy +12y^2
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sign  of  3rd  term  is  (+) therefore  both  factors  have  same  sign
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sign  of  second  term  is  (+) ,,,therefore both  factors  are  (+)
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factors  of  1st  term  are,,  1*4,,2*2
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Factors  of  3rd  term  are, 1*12,,2*6,,3*4,,
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Seeking  a  combination  whose  factors  add  to  19
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Try,,,4*4 + 1*3 = 16+3 = 19
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(4x +3y)(1x +4y)
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