Question 211362
25x^2+16=0
25x^2=-16


{{{x^2= -16/25 }}}
{{{x= 0+-sqrt(-16/25) }}}
{{{x= 0+-sqrt(16/25)*sqrt(-1)}}}
{{{x=0+-i*(4/5) }}}  

R^2


Dr. Robert J. Rapalje