Question 211318
log2 (1/16) = y
Write the exponent equiv of logs
{{{2^y = (1/16)}}}
We know that 2^-1 = 1/2 and that 1/16 = 1/2 * 1/2 * 1/2 * 1/2
therefore
y = -4
{{{2^(-4) = (1/16)}}}