Question 29148
Note - here "*" is a mulitipication sign and "/" division sign


total money which Jose invested  = $5,000.00

Let money invested in bond fund = $x..........equation no, (1)

Therefore, Money invested in market fund = ($5,000.00 - x).....Equation no,(2)  
(because jose invested money in market fund which is left after investing in bond fund and we are given that he has totally invested $5,000.00 in both)

Now,total interest recieved by him = $220

Therefore according to question,we get the following equation:-

 $220 = 5% of bond fund + 4% of market fund

  220 = 5% of x + 4% of ($5,000.00 - x)

  220 =  5/100 of x +   4/100   of (5,000.00 - x) (here 5/100 and 4/100 means that 5 and 4 are been divided by 100)
        
Since "of" is converted in Mutiply sign "*" and after solving brackets,,We get...

  220 =  5/100  * x  +  4/100  * 5,000.00  -  4/100  * x
        
now, after mutipication, we get ...

  220 = 5/100 x  + 20,000.00/100 -  4/100 x
       
Now, after taking L.C.M. we get

   220 =  (5x + 20,000.00 - 4x)/100
         
Now, after cross mutipication,we get...

 
  22,000.00 = 5x + 20,000.00 - 4x 

and  22,000.00 - 20,000.00 = 5x - 4x

      2,000.00 = x

 Now, put the value of x in equation no, (1)....we get

  Money invested in Bond fund = $x
                              = $2,000.00

  ANd Money invested in market fund = $5,000.00 - x
                                    = $5,000.00 - 2,000.00
                                    = $3,000.00

(Moreover if you want to check your answer. Take 5% of bond fund and 4% of market, the sum of both would have to be equal to $220 which is given total money recieved after investing in both the funds)