<PRE><B>Question 211262</B>
Find three consecutive integers such that the sum of the first plus one-third of the second plus three-fourths of the third is 31. 
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1st: x-1
2nd: x
3rd: x+1
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Equation:
x-1 = (1/3)x + (3/4)(x+1)
Multiply thru by 12 to get:
12x - 12 = 4x + 9x + 9
x = -21
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1st: x-1 = -22
2nd: x = -21
3rd: x = -20
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Cheers,
Stan H.</PRE>