Question 210963
Solve the linear system: 2x + 7y = 41, 2y = 3x + 1 
;
We can rearrange this to use elimination
:
+2x + 7y = 41
-3x + 2y = 1
:
Multiply 1st equation by 3, multiply the 2nd equation by 2
+6x + 21y = 123
-6x + 4y = 2
---------------addition eliminates x, find y
0 + 25y = 125
y = {{{125/25}}}
y = 5
:
Find x using the 1st original equation
2x + 7(5) = 41, 
2x + 35 = 41
2x = 41 - 35
x = {{{6/2}}}
x = 3
;
:
Check solution in 2nd original equation:
2(5) = 3(3) + 1