Question 211194
Let x be the amount of money invested at 5%.
Then the amount invested at 7% is 6000 - x.
The interest earned from the money invested at 5% is x*5%
The interest earned from the money invested at 7% is (6000 - x)*7%
As the total interest earned from the two investments is given as $372, we have:
x*5% + (6000 - x)*7% = 372
Solving for x, we get
5x + 7(6000 - x) = 37200 (multiply both sides by 100)
5x + 42000 - 7x = 37200
-2x + 42000 = 37200
-2x = -4800
x = 2400
So $2,400 is invested at 5%, and $6,000 - $2,400 = $3,600 is invested at 7%.