<PRE><B>Question 211128</B>
Simple, you don&#39;t factor polynomials with negative exponents.  You put the negative exponents in the denominator and the get a common denominator and solve that way. You will end up having to factor but the exponents will be positive.   &lt;br&gt;

3x^-2 -7x^-1 -6 = 0
{{{3/x^2 - 7/x - 6 = 0}}}&lt;br&gt;

The common denominator on this problem is going to be x^2 so multiply the second part of the equation by x and the 6 by x^2.  This will get us:&lt;br&gt;

{{{(3 - 7x - 6x^2)/x^2 = 0}}}&lt;br&gt;

Now we multiply both sides by x^2 and that leaves us with the following polynomial:&lt;br&gt;

3 - 7x - 6x^2 = 0&lt;br&gt;

Now we solve this like any regular polynomial.&lt;br&gt;

3 - 7x - 6x^2 = 0
6x^2 + 7x - 3 = 0 
(2x+3)(3x-1) = 0
2x+3 = 0 and 3x-1 = 0 
x = -3/2 and x = 1/3&lt;br&gt;

I will leave the second equation for you to do but its solved in a similar manor.
</PRE>