<PRE><B>Question 210984</B>
Please help find the equation of a line that is perpendicular to the line 
y=-x+5 and passes through the point(-2,3).
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The given line has a slope of -1, so the equation you 
want must have a slope of +1.
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Equation form is y = mx + b and you have y=3 when x = -2.
So solve for &quot;b&quot; as follows:
3 = 1(-2) + b
b = 5
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Equation:
y = x + 5
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{{{graph(400,300,-10,15,-10,10,-x+5,x+5)}}}
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Cheers,
Stan H.
</PRE>