Question 210891
3[x-(2-x)-2x]=3(4-x) ... Start with the given equation.



{{{3x-3(2-x)-6x=3(4-x)}}} Distribute



{{{3x-6+3x-6x=12-3x}}} Distribute again.



{{{-6=12-3x}}} Combine like terms on the left side.



{{{-6-12=-3x}}} Subtract 12 from both sides.



{{{-18=-3x}}} Combine like terms.



{{{-18/(-3)=x}}} Divide both sides by -3 to isolate 'x'.



{{{6=x}}} Reduce



{{{x=6}}} Rearrange the equation



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Answer:


So the solution is {{{x=6}}} 






Check:


3[x-(2-x)-2x]=3(4-x) ... Start with the given equation.



3[6-(2-6)-2*6]=3(4-6) ... Plug in {{{x=6}}} (ie replace each 'x' with 6)



3[6-(2-6)-12]=3(4-6) ... Multiply



3[6-(-4)-12]=3(-2) ... Combine like terms.



3[6+4-12]=3(-2) ... Rewrite -(-4) as +4



3[-2]=3(-2) ... Combine like terms.



-6=-6 ... Multiply



Since the equation is true, this verifies the solution {{{x=6}}}