Question 210900
f(x)=x^2 + 2x + 5 
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The axis of symmetry is the line x = -b/2a
x = -2/2 = -1
x = -1 (equation of axis of symmetry)
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f(x)=x^2 + 2x + 5 
f(x)=(x^2 + 2x) + 5 
f(x)=(x^2 + 2x + __ ) + 5 
f(x)=(x^2 + 2x + 1 ) + 5 - 1
f(x)=(x+1)^2 + 4 
f(x)=(x-(-1))^2 + 4 (vertex form)
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vertex is at (-1,4)