Question 210679
They give you:
P = x^2 + x – 10
.
Set P to zero to find out when you have NO profit:
0 = x^2 + x – 10
.
Solving for x will give you where it crosses the x-axis:
0 = x^2 + x – 10
Since we can't factor, we apply the quadratic equation to get:
x = {2.7, -3.7}
We can throw out the negative solution leaving:
x = 2.7
.
Values of x where P is POSITIVE:
x > 2.7
.
Details of quadratic to follow:
*[invoke quadratic "x", 1, 1, -10 ]