Question 29077
Could you help me find the x-intercepts of the equation y=-2x^2-8x+20?
X INTERCEPT MEANS THE X COORDINATE OF THE POINT/POINTS , WHERE THE GRAPH CUTS X AXIS...THAT IS WHERE Y COORDINATE IS ZERO...SO PUT Y=0 AND FIND X VALUES.HERE WE HAVE
-2x^2-8x+20=0...OR......X^2+4X-5=0
X^2+5X-X-5=0
X(X+5)-1(X+5)=0
(X-1)(X+5)=0
X=1 AND X=-5 ...SO THE X INTERCEPTS ARE +1 AND - 5