Question 210645
(1) {{{2x = 3}}}
(2) {{{-3y = 6}}}
Divide both sides of (1) by {{{2}}}
(1) {{{x = 3/2}}}
Divide both sides of (2) by {{{-3}}}
(2) {{{y = -2}}}
The 1st equation has the same value of {{{x}}}
no matter what {{{y}}} is from minus
infinity to plus infinity. It is a
vertical line at {{{x = 3/2}}}
The 2nd equation has the same value of {{{y}}}
no matter what {{{x}}} is from minus
infinity to plus infinity. It is a
horizontal line at {{{y = -2}}}
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The lines are therefore perpendicular