Question 210648
Solve:
{{{x^2-6x+13 = 0}}}?
Using the quadratic formula: {{{x = (-b+-sqrt(b^-4ac))/2a}}} and, in this problem: a = 1, b = -6, and c = 13.
{{{x = (-(-6)+-sqrt((-6)^2-4(1)(13)))/2(1)}}} Evaluate:
{{{x = (6+-sqrt(36-52))/2}}}
{{{x = (6+-sqrt(-16))/2}}}
{{{x = 6/2+sqrt(-16)/2}}} or {{{x = 6/2-sqrt(-16)/2}}} and these can be simplified to:
{{{x = 3+(4/2)sqrt(-1)}}} or {{{x = 3-(4/2)sqrt(-1)}}}
{{{highlight(x = 3+2i)}}} or {{{highlight(x = 3-2i)}}}