Question 210449
{{{sqrt(2-(4)/z^2+(2)/z^4)}}}
Let's add together what is under the radical first. LCD=z^4.
{{{sqrt((2z^4-4z^2+2)/z^4)}}}
Pull out the Z^4 term in denominator:
{{{(1/z^2)sqrt(2z^4-4z^2+2)}}}
Factor out a 2:
{{{(1/z^2)sqrt(2(z^4-2z^2+1))}}}
Factor:
{{{(1/z^2)sqrt(2(z^2-1)(z^2-1))}}}
Pull out the z^2-1 term:
{{{((z^2-1)/z^2)sqrt(2)}}}
I think this is about as far as you can go.
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Good Luck,
tutor_paul@yahoo.com