Question 210519
Question: " The difference of two numbers is 67. The larger number is three less than six times the smaller number. Find the numbers." 
I tried solving it like this:
x-y=67 
larger number=6y-3
(6y-3)-y=67
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14 and 81 does work.
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x = larger #
y = smaller #
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x-y = 67
x = 6y-3
Sub for x into the 1st eqn
(6y-3) - y = 67
5y = 70
y = 14
x = 81