Question 29104
The correct problem should be something like this:
{[(x^2-2x-3)/(x+1)]divided by [(x^2+x-12)/(x^2)]}-1


{[(x^2-2x-3)/(x+1)]divided by [(x^2+x-12)/(x^2)]}-1
= {[(x-3)(x+1)/(x+1)]divided by [(x+4)(x-3)/(x^2)]}-1
={[(x-3)]divided by [(x+4)(x-3)/(x^2)]}-1 (cancelling (x+1)
={[(x-3)]mulitplied by[(x^2)/(x+4)(x-3)]}-1 
(if the division sign is changed into multiplication symbol then then the fraction after the division sign is reciprocated)
={[(x-3)]X[(x^2)/(x+4)(x-3)]}-1
={[(x-3)(x^2)/(x+4)(x-3)]}-1
=[(x^2)/(x+4)]-1 (cancelling (x-3)
=[(x^2)-1(x+4)]/(x+4)
= (x^2-x-4)/(x+4)