Question 210519
The difference of two numbers is 67. The larger number is three less than six times the smaller number. Find the numbers." 
I tried solving it like this:
x-y=67 
larger number=6y-3
(6y-3)-y=67
The answers in the back of the book says 14 and 81.
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Since x-y = 67, the "x" must be the larger number.
Equation:
x = 6y-3
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Substitute that into x-y=67 to get:
6y-3 - y = 67
5y = 70
y = 14
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Substitute that and solve for "x":
x = 6*14 -3
x = 84-3
x = 81
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Cheers,
Stan H.