Question 210515
<font size = 7 color="red"><b>Edwin's solution:</font></b>
{{{3x^2- 12x=0}}} solve for x
<pre><font size = 4 color= "indigo"><b>
Factor out 3x on the left

{{{3x(x- 4)=0}}}

The two factors are {{{3x}}} and {{{x-4}}}

Set each equal to zero:

Setting the first factor = 0:

{{{3x=0}}}
{{{3x/3=0/3}}}
{{{x=0}}}

Setting the second factor = 0:

{{{x-4=0}}}
{{{x=4}}}

So there are two solutions, {{{x=0}}} and {{{x=4}}}

Edwin</pre>