<PRE><B>Question 210131</B>
y = 1/5x+5 - 3/x+1 + 7/5
Assume it&#39;s
y = {{{1/(5x+5) - 3/(x+1) + 7/5}}}
:
{{{1/(5x+5) - 3/(x+1) + 7/5}}} = 0
:
Factor out 5:
{{{1/(5(x+1)) - 3/(x+1) + 7/5}}}
:
Common denominator 5(x+1) multiply equation, results:
1 - 5(3) + 7(x+1) = 0
:
1 - 15 + 7x + 7 = 0
:
7x - 7 = 0
:
7x = 7
:
x = 1
;
:
Check in original equation 
{{{1/(5(1)+5) - 3/(1+1) + 7/5}}} = 0
{{{1/10 - 3/2 + 7/5}}} = 0
{{{1/10 - 15/10 + 14/10}}} = 0</PRE>