Question 210295
The function f is defined by y = f(x) = 2 ln 4x, 0:01 <= x >= 1. 
c) Plot f from x = 0:01 to x = 1 and then plot f^(-1) on the same axes but only for domain values of x given by the range of f.
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Find the equation of f^-1(x)
Start with y = 2ln(4x)
x = 2ln(4y)
ln(4y) = x/2
4y = e^(x/2)
y = (1/4)e^(x/2)
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Graph y = 2ln(4x) and (1/4)e^(x/2)
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{{{graph(400,300,-10,10,-10,10,2*ln(4x),(1/4)2.71828^(x/2))}}}
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You will have to pick the segment of f(x) where 0.01<x<1
and the segment of f^-1(x) that has the range of f as 
its domain.
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Notice that the two curves are symmetric to the line y = x.
Cheers,
Stan H.