Question 210251
If I'm getting this right, you just want the distance from (8,7) to (3,5) right?



Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(8,7\right)]. So this means that {{{x[1]=8}}} and {{{y[1]=7}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(3,5\right)].  So this means that {{{x[2]=3}}} and {{{y[2]=5}}}.



{{{d=sqrt((x[1]-x[2])^2+(y[1]-y[2])^2)}}} Start with the distance formula.



{{{d=sqrt((8-3)^2+(7-5)^2)}}} Plug in {{{x[1]=8}}},  {{{x[2]=3}}}, {{{y[1]=7}}}, and {{{y[2]=5}}}.



{{{d=sqrt((5)^2+(7-5)^2)}}} Subtract {{{3}}} from {{{8}}} to get {{{5}}}.



{{{d=sqrt((5)^2+(2)^2)}}} Subtract {{{5}}} from {{{7}}} to get {{{2}}}.



{{{d=sqrt(25+(2)^2)}}} Square {{{5}}} to get {{{25}}}.



{{{d=sqrt(25+4)}}} Square {{{2}}} to get {{{4}}}.



{{{d=sqrt(29)}}} Add {{{25}}} to {{{4}}} to get {{{29}}}.



So our answer is {{{d=sqrt(29)}}} 



Which approximates to {{{d=5.385}}} 



So the distance between the two points (8,7) and (3,5) is approximately 5.385 units.