Question 29099
Please help me solve the equation (x^2-3x)/(4x^2-3x)*(4x^2-16)
I have tried to follow the instructions in my book by factoring it to:
x(x-3)/4x(x-2)*(2x+4)(2x-4)
can you please show the problem step by step since i have others like it that i would like to know how to solve
Thank You,
Alyssa

If the problem is [(x^2-3x)/(4x^2-8x)]*(4x^2-16)
=[x(x-3)/4x(x-2)]X4(x^2-4)
=[(x-3)/4(x-2)]X4(x+2)(x-2)  (cancelling out x)
=(x-3)(x+2)