Question 210087
{{{x/(x^2-3x-10)+2/(x^2-3x-10)}}} Start with the given expression.



Since the denominators are equal, we can combine the fractions.



{{{(x+2)/(x^2-3x-10)}}} Combine the numerators over the common denominator.



{{{(x+2)/((x+2)(x-5))}}} Factor the denominator.



{{{highlight((x+2))/(highlight((x+2))(x-5))}}} Highlight the common terms.



{{{cross((x+2))/(cross((x+2))(x-5))}}} Cancel out the common terms.



{{{1/(x-5)}}} Simplify



So {{{x/(x^2-3x-10)+2/(x^2-3x-10)=1/(x-5)}}} where {{{x<>-2}}} or {{{x<>5}}}