Question 210095
Ok, the key here is to find the change in the baloon's height in the two-minute observation period.
You have a good starting point with the right triangle but actually, you would have two right triangles having the same base (300 meters) but different heights.
You can calculate these heights using the tangent function because you are given the two appropriate angles (25 degs. and 60 degs.)
As you probably know, the tangent of the given angles is just the height divided by the base. So we can find the two heights as follows, starting with the lower height which we can call {{{h[1]}}}:
{{{h[1] = 300*Tan(25)}}} ...and the upper height is:
{{{h[2] = 300*Tan(60)}}} Subtracting these two:
{{{h[2]-h[1] = 300*(Tan(60)-Tan(25))}}}
{{{h[2]-h[1] = 300*(1.2657)}}}
{{{h[2]-h[1] = 379.723}}}Meters.
So the ballon ascended a distance of 379.723 meters in 2 minutes (10:02 - 10:00). Converting this to seconds we have a speed of:
{{{379.723/120}}} meters per second.  Performing the indicated division, we get:
{{{highlight(3.16)}}}meters per second (rounded to two decimal places.)