Question 210045
A rocket is launched from atop a 43-foot cliff with an initial velocity of 70 feet per second. The height of the rocket t seconds after launch is given by the equation h = -16t^2 + 70t + 43. Graph the equation to find out how long after the rocket is launched it ill hit the ground. Estimate your answer to the nearest tenth of a second.
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h = -16t^2 + 70t + 43
Set h = 0 and solve for t
-16t^2 + 70t + 43 = 0
*[invoke solve_quadratic_equation -16,70,43]
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Use the positive number.
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BTW, rockets have motors and they accelerate when launched.  This is a ballistics problem, and the "rocket" just rises and falls due to initial forces and gravity.
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