Question 210014
the sum of two integers is ten. three times the larger integer is three less than eight times the smaller integer
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Let the numbers be a and b:
Equations:
a + b = 10
3*a = 8*b-3
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Rearrange to solve for "b":
a = 10-b
3(10-b) = 8b  - 3
30-3b = 8b -3
11b = 33
b = 3
Therefore a = 10-3 = 7
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Cheers,
Stan H.
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